Answer:
T₂ = 1937.68 N
Explanation:
First, we will calculate the weight of the object:
[tex]W = mg = (478\ kg)(9.81\ m/s^2)\\W = 4689.18\ N[/tex]
Now, we will calculate the resultant tension in the ropes. Since the ropes are perpendicular. Therefore,
[tex]T = \sqrt{T_1^2+T_2^2}\\[/tex]
where,
T = Resultant Tension
T₁ = Tension in rope 1
T₂ = Tension in rope 2
According to the given condition tension in the first rope is 2.2 times the tension in the second rope:
T₁ = 2.2 T₂
Therefore
[tex]T = \sqrt{(2.2T_2)^2 + T_2^2}\\\\T = 2.42T_2[/tex]
Now, the weight of the object must be equal to the resultant tension for equilibrium:
[tex]T = W\\2.42T_2 = 4689.18\ N\\\\[/tex]
T₂ = 1937.68 N
