A 2.0   kg 2.0kg2, point, 0, start text, k, g, end text cart moving right at 5.0   m s 5.0 s m ​ 5, point, 0, start fraction, start text, m, end text, divided by, start text, s, end text, end fraction on a frictionless track collides with a 3.0   kg 3.0kg3, point, 0, start text, k, g, end text cart initially at rest. The 2.0   kg 2.0kg2, point, 0, start text, k, g, end text cart has a final speed of 1.0   m s 1.0 s m ​ 1, point, 0, start fraction, start text, m, end text, divided by, start text, s, end text, end fraction to the left. What is the final speed of the 3.0   kg 3.0kg3, point, 0, start text, k, g, end text cart?

Respuesta :

Answer:  The answer is 4.0 m/s.

Explanation: khan acadmey.

The final speed of the 3.0  kg cart is  4 m/s.

What is conservation of momentum principle?

When two bodies of different masses move together each other and have head on collision, they travel to same or different direction after collision.

The external force is not acting here, so the initial momentum is equal to the final momentum. For elastic collision, final velocities is different for both the bodies.

m₁u₁ +m₂u₂ = m₁v₁ +m₂v₂

A 2.0  kg cart moving right at 5.0  m/s on a frictionless track collides with a 3.0 kg  cart initially at rest. The 2.0   kg cart has a final speed of 1.0 m/s  to the left.

Substitute the values for m₁ = 2kg, m₂ =3kg, u₁ =5 m/s and u₂ =0 m/s, then the final velocity will be

3x0 +2x5 = -2x1 + 3v₂

v₂ = 4 m/s

Thus, the the final velocity 3.0  kg cart is  4 m/s.

Learn more about conservation of momentum principle.

https://brainly.com/question/14033058

#SPJ2