Answer:
proving question
Step-by-step explanation:
The triangles have been drawn along with the circle and the figure is attached.
In ΔABD and ΔDCA
i) ∠ BAD = ∠ ADC = 90° [ Angle in a semicircle is always 90°]
ii) BD = AC [ both are diameters]
iii) AD = AD [ AD is a common side in both triangle]
Therefore, Δ ABD and ΔDCA are congruent to each other by RHS rule.
