Answer:
B has a smaller initial population of 500
Step-by-step explanation:
Given
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Required
The bacteria with the smaller initial population
The initial population is at x = 0
For bacteria A;
[tex]A(x) = 600[/tex] when [tex]x = 0[/tex]
For bacteria B, we have:
[tex]B(x) = 500(2)^x[/tex]
Substitute 0 for x
[tex]B(x) = 500(2)^0[/tex]
[tex]B(x) = 500*1[/tex]
[tex]B(x) = 500[/tex]
So; when x = 0
[tex]A(x) = 600[/tex] and [tex]B(x) = 500[/tex]
Because; 500 < 600
We can conclude that B has a smaller initial population of 500
