Answer:
a. Too close to zero.
b. Higher than zero.
c. Lower than zero.
d. Too close to zero.
e. Higher than zero.
Explanation:
The entropy of a reaction, S, is positive when the disorder of the system increases. That is:
Solid → Liquid → Gas S>0
When S<0, the disorder decreases:
Gas → Liquid → Solid S<0
Thus:
a. H2(g)+Cl2(g)→2HCl(g)
2 moles of gas produce 2 moles of gas:
S too close to zero.
b. 2H2O2(l)→2H2O(l)+O2(g)
A liquid is producing a gas:
S>0
c. CO(g)+3H2(g)→CH4(g)+H2O(g)
4 moles of gas produce 2 moles of gas, the disorder decreases:
S<0
d. CH4(g)+2O2(g)→CO2(g)+2H2O(g)
3 moles of gas produce 3 moles of gas:
S too close to zero.
e, 2SO3(g)→2SO2(g)+O2(g)
2 moles of gas produce 3 moles of gas.
S>0
