Answer:
5
E 4(4)^n-1
n-1
Step-by-step explanation:
The series is being multiplied by 4 each time making it a geometric series. Which means that the common ratio is 4, r=4.
Secondly, you can determine the value of K by counting the number of numbers in the series. In this case there are 5, k=5.
Finally, the last value we need to find is a1 which is found by looking at the first value in the set, a1=4.
Once we have all of these values, we put them into the finite Sigma Notation equation.
k
E a1(r)^n-1
n-1
The values go where their equivalents are, and then we have our answer:
5
E 4(4)^n-1
n-1
