If you were provided with 4.25 grams of CaCl2, how many formula units of AgCl would be produced?

4 AgNO3 (aq) + 2 CaCl2 (aq) → 4 AgCl (s) + 2 Ca(NO3)2 (aq)
a
6.9 x1022 formula units

b
4.6 x1022 formula units

c
2.3 x1022 formula units

d
9.2 x1022 formula units