The question is incomplete, the complete question is;
Some carbonated beverages are made by forcing carbon dioxide gas into a beverage solution. When a bottle
of one kind of carbonated beverage is first opened, the beverage has a pH value of 3.
After the beverage bottle is left open for several hours, the hydronium ion concentration in the beverage
solution decreases to 1/1000 of the original concentration. Determine the new pH of the beverage solution.
Answer:
6
Explanation:
Recall that
pH= -log[H3O^+]
Hence, [H^+] when the drink was first opened;
3 = -log[H^3O+]
[H^+] = Antilog(-3)
[H30^+] = 1 * 10^-3
Since [H3O^+] decreases to 1/1000 times its original value;
New [H3O^+] = 1 * 10^-3 * 1/1000 = 1 * 10^-6
Hence,
New pH = -log[1 * 10^-6]
New pH = 6
