[tex]\huge\bold{Given :}[/tex]
Angle 1 = 40°
Angle 2 = x°
Angle 3 = ( x + 28 )°
[tex]\huge\bold{To\:find :}[/tex]
The value of x.
[tex]\large\mathfrak{{\pmb{\underline{\orange{Solution}}{\orange{:}}}}}[/tex]
[tex]{\boxed{\mathcal{\purple{The\:value\:of\: x \:is\:56 ° .\:}}}}[/tex]✅
[tex]\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\orange{:}}}}}[/tex]
We know that,
[tex]\sf\pink{Sum\:of\:angles\:of\:a\:triangle\:=\:180°}[/tex]
➪ ∠ 1 + ∠ 2 + ∠ 3 = 180°
➪ 40 + x° + x° + 28° = 180°
➪ 2x° + 68° = 180°
➪ 2x° = 180° - 68°
➪ x° = [tex] \frac{112° }{2} [/tex]
➪ x° = 56°
[tex]\sf\red{Therefore, \:the\: value \:of \:x\: is \:56°.}[/tex]
[tex]\large\mathfrak{{\pmb{\underline{\blue{To\:verify}}{\blue{:}}}}}[/tex]
∠ 1 + ∠ 2 + ∠ 3 = 180°
✒ 40° + 56° + 56° + 28° = 180°
✒ 180° = 180°
✒ L. H. S. = R. H. S.
[tex]\boxed{Hence\:verified.}[/tex]
[tex]\bold{ \green{ \star{ \orange{Hope\:it\:helps.}}}}⋆[/tex]
