Answer. First things first... Balance the Chemical Equation
2FeCl3 + 3(NH4)2CO3 ---------> 6NH4Cl + Fe2(CO3)3
Its balanced Now.
200g of FeCl3 ---Given this... We can get jts reacting Moles
Mole = Mass/Molar Mass
Molar Mass of FeCl3 = 56 + (35.5)x3=162.5gmol-¹
Mole=200/162.5 =1.231moles of FeCl3
From the equation of Reaction
When 2mole of FeCl3 reacts.... It produces 1mole of Iron III carbonate [Fe2(CO3)3]
Since Mole ratio of reaction between both is 2:1
Therefore When 1.231moles of FeCl3 react....
1.231/2 moles of Fe2(CO3)3 will be produced.
= 1.231/2 = 0.616moles.
0.616Moles of Fe2(CO3)3 will be produced
Recall MASS =MOLE X MOLAR MASS
MOLAR MASS OF FE2(CO3)3= 56(2) + (60)(3)=292gmol-¹
MASS = 0.616 x 292 =179.872g ~ 180g of Fe2(CO3)3 Will Be Produced.
OPTION A SEEMS TO BE THE CLOSEST. THAT SHOULD BE OUR ANSWER. I MAY HAVE MISSED IT A BIT BECAUSE OF SOME APPROXIMATIONS.
BYE!
Answer:
[tex]FeCl₃ + (NH₄)₂CO₃ → NH₄Cl + Fe₂(CO₃)₃[/tex]
first balance the chemical equation
first balance the chemical equation[tex]2FeCl₃ + 3(NH₄)₂CO₃ → 6NH₄Cl + Fe₂(CO₃)₃[/tex]
2FeCl₃=2*162=324g
6NH₄Cl=6*53.5=321g
324 g of FeCl₃ gives 321 g of NH₄Cl
200g of FeCl₃ gives 321/324*200=198.14 g of NH₄Cl
in nearest value it is 198g/mole
The number of grams of ammonium chloride (NH4Cl) that will be produced is C.198___ grams.
