Answer:
[tex]y = 4(x - 4)^2 - 2[/tex]
or
[tex]y=4x^2 -32x + 62[/tex]
Step-by-step explanation:
Given
[tex]V = (4,-2)[/tex] --- vertex
[tex]P = (2,14)[/tex] --- point
Required
The equation of the parabola
The equation of the parabola is of the form
[tex]y = a(x - h)^2 + k[/tex]
Where
[tex]V (4,-2) = (h,k)[/tex] ---- the vertex
So, we have:
[tex]y = a(x - h)^2 + k[/tex]
[tex]y = a(x - 4)^2 - 2[/tex]
In [tex]P = (2,14)[/tex], we have:
[tex](x,y) = (2,14)[/tex]
Substitute [tex](x,y) = (2,14)[/tex] in [tex]y = a(x - 4)^2 - 2[/tex]
[tex]14 = a(2 - 4)^2 - 2[/tex]
[tex]14 = a(- 2)^2 - 2[/tex]
[tex]14 = a*4 - 2[/tex]
[tex]14 = 4a - 2[/tex]
Collect like terms
[tex]4a = 14 +2[/tex]
[tex]4a = 16[/tex]
Divide both sides by 4
[tex]a= 4[/tex]
So:
[tex]y = a(x - 4)^2 - 2[/tex] becomes
[tex]y = 4(x - 4)^2 - 2[/tex]
Open bracket to express the equation in standard form
[tex]y=4(x^2 -8x + 16) - 2[/tex]
[tex]y=4x^2 -32x + 64 - 2[/tex]
[tex]y=4x^2 -32x + 62[/tex]
