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A 90% confidence interval for the mean percentage of airline reservations being canceled on the day of the flight is (3.9%, 7.3%). What is the point estimator of the mean percentage of reservations that are canceled on the day of the flight? 3.65% 5.60% 1.70% 3.4%

Respuesta :

Answer:   5.60%

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Work Shown:

Find the midpoint of the percentages given.

A = 3.9

B = 7.3

C = midpoint of A and B = point estimate

C = (A+B)/2

C = (3.9+7.3)/2

C = 11.2/2

C = 5.60

5.60% is the point estimate

Side note: The margin of error is B-C = 7.3-5.6 = 1.70%, or you could say C-A = 5.6 - 3.9 = 1.70%

The mean percentage of reservations that are canceled on the day of the flight is equal to the 5.60%

We have to determine the midpoint of the percentages given.

A = 3.9

B = 7.3

C = midpoint of A and B = point estimate

What is the formula for the midpoints?

C = (A+B)/2

C = (3.9+7.3)/2

C = 11.2/2

C = 5.60

5.60% is the point estimate

Side note: The margin of error is

B-C = 7.3-5.6

B-C= 1.70%, or you could say

C-A = 5.6 - 3.9

C-A= 1.70%

Therefore the midpoint of B and C is 1.70% and the midpoint in between C-A is 1.70%.

To learn more about the midpoint visit:

https://brainly.com/question/5566419

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