Answer:
The molality is "6.86 m".
Explanation:
Given:
Mass of of HCL,
= 25 g
Mass of water,
= 100 g
Density,
= 1.19 g/mL
Total mass of solution,
= 125 g
Now,
The number of moles of HCl will be:
= [tex]\frac{25}{36.458}[/tex]
= [tex]0.6857[/tex]
The solution volume will be:
= [tex]\frac{125}{1.19}[/tex]
= [tex]105.04 \ mL[/tex]
hence,
The molality will be:
= [tex]\frac{No. \ of \ moles \ of \ solute}{Mass \ of \ solvent (Kg)}[/tex]
= [tex]\frac{0.6857}{0.1}[/tex]
= [tex]6.857 \ m[/tex]
or,
= [tex]6.86 \ m[/tex]
