A bag contains 4 yellow, 2 red, and 6 green marbles. two marbles are drawn. the first is replaced before the second is drawn. a random variable assigns the number of red marbles to each outcome. calculate the expected value of the random variable.
a. 0.67
c. 0.17
b. 0.56
d. 0.33

There are 2 red marbles, in 12, the probability to take one red is 2/12. Is important to remember that the first marble was replaced before the second outcome, so the chance for the second is also 2/12:

2/12 = 1/6 = 0.1666 ≈ 0.17

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ewomazinoade ewomazinoade · Answer 2 · 2022-05-16T13:00:03+02:00

The expected value of the random variable that assigns the number of red marbles to each outcome is 0.17.

What is the probability?

Probability is used to estimate how likely an event would happen. The probability the event occurs with certainty is 1 and the probability that the event does not occur with certainty is 0.

Expected value = number of red marbles / total number of marbles

2/12 = 0.17

To learn more about probability, please check: https://brainly.com/question/13234031

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A bag contains 4 yellow, 2 red, and 6 green marbles. two marbles are drawn. the first is replaced before the second is drawn. a random variable assigns the number of red marbles to each outcome. calculate the expected value of the random variable. a. 0.67 c. 0.17 b. 0.56 d. 0.33

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What is the probability?

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A bag contains 4 yellow, 2 red, and 6 green marbles. two marbles are drawn. the first is replaced before the second is drawn. a random variable assigns the number of red marbles to each outcome. calculate the expected value of the random variable.
a. 0.67
c. 0.17
b. 0.56
d. 0.33