Answer:
1680
Step-by-step explanation:
The given word is "PALINDROME".
The number of ways in [tex]$\text{which six of the letters of the word}$[/tex], "PALINDROME" be selected and is written in a row if the first two letters must be PA or the last two letters are ME is given by :
[tex]$^8C_4 \times 4! = 4 \times 7 \times 6 \times 5$[/tex]
= 1680
Therefore, the word "PALINDROME" can be written in 1680 ways such that the first two letters are PA in a row or the last two letters are ME.
