Three resistors 4ohms 6ohms8ohms are connected in series and are connected to cell of EMF 60volt and negilible resistance calculate the current in circuit , potential difference in resistors ,total terminal potential difference in circuit and lost volt​

Respuesta :

Explanation:

Given that,

Three resistors 4ohms 6ohms 8ohms are connected in series and are connected to cell of EMF 60volt.

The equivalent resistance in series combination is given by :

R = R₁ + R₂ +R₃

Put all the values,

R = 4 + 6 + 8

R = 18 ohms

Let I is the current in circuit. So,

[tex]I=\dfrac{V}{R}\\\\I=\dfrac{60}{18}\\\\I=3.33\ A[/tex]

Potential difference in 4 ohms,

[tex]V_1=IR_1\\\\V_1=3.33\times 4\\\\=13.32\ V[/tex]

Potential difference in 6 ohms,

[tex]V_2=IR_2\\\\V_2=3.33\times 6\\\\=19.98\ V[/tex]

Potential difference in 8 ohms,

[tex]V_3=IR_3\\\\V_3=3.33\times 8\\\\=26.64\ V[/tex]

Terminal potential difference in circuit is :

V = IR

Put all the values,

V = 3.33 × 18

V = 59.94 volts

Hence, this is the required solution.