9. What is the total number of grams of NaOH (formula mass = 40.) needed to make 1.0 liter of a 0.20 M solution?

(1) 20. g (2) 2.0 g (3) 80. g (4) 8.0 g​

Respuesta :

Answer:

8 gram

Explanation:

in case of NaOH, normality=molarity

so normality=molarity×acidity or basicity(in case of NaOH it's 1)

then

weight of NaOH required = volume in ml × equivalent weight × normality / 1000

so

1000× 40× 0.2/1000

=8 gram

The total mass of sodium hydroxide (NaOH) needed to make the solution is 8 g (Option 4)

How to determine the mole of NaOH

  • Volume = 1 L
  • Molarity = 0.2 M
  • Mole of NaOH =?

Molarity = mole / Volume

0.2 = mole of NaOH / 1

Mole of NaOH = 0.2 mole

How to determine the mass of NaOH

  • Mole of NaOH = 0.2 mole
  • Molar mass of NaOH = 40 g/mol
  • Mass of NaOH =?

Mass = mole × molar mass

Mass of NaOH = 0.2 × 40

Mass of NaOH = 8 g

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