Answer:
the total charge which crosses into the collector is 60 nC
Explanation:
Given the data in the question;
current flowing into the collector lead of the bipolar junction transistor (BJT); i = 1 nA = 10⁻⁹ A
no charge was transferred in or out of the collector lead prior to t = 0
the current flow time t = 1 min = 60 sec
Now we write the relation between current, charge, and time;
i = dq / dt
where i is current, q is charge and t is time. { d refers to change }
Now,
[tex]q=\int\limits^t_{t=0} {i(t)} \, dt[/tex]
[tex]q=\int\limits^{t=60}_{t=0} { (10^{-9}) } \, dt[/tex]
[tex]q = ( 10^{-9}) (t)_0^{60[/tex]
[tex]q = ( 10^{-9}) ( 60 - 0 )[/tex]
q = 60 × 10⁻⁹ C
q = 60 nC
Therefore, the total charge which crosses into the collector is 60 nC
