Answer:
There is sufficient evidence. A further explanation is provided below.
Step-by-step explanation:
According to the question,
The alternative as well as null hypothesis will be:
[tex]H_0:\mu = 16[/tex]
[tex]H_a:\mu>16[/tex]
The test statistics will be:
⇒ [tex]z = \frac{\frac{\bar x - \mu}{\sigma} }{\sqrt{n} }[/tex]
By putting the values, we get
⇒ [tex]=\frac{\frac{16.06-16}{0.24} }{\sqrt{96} }[/tex]
⇒ [tex]=\frac{\frac{0.06}{0.24} }{\sqrt{96} }[/tex]
⇒ [tex]=2.45[/tex]
Or,
The p-value will be:
= 0.0071
i.e.,
⇒ [tex]p-value< \alpha[/tex]
Thus the above is the correct answer.
