kim736
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A rock is thrown horizontally from a height of 6.00 m. Which of the following is the time required for the rock to reach the ground ?

Respuesta :

rvillalta2002

Answer:

t=10.95 seg

Explanation:

The vertical component of velocity is 0, so, the time in air can be calculated

[tex]h=v_ot-\frac{1}{2}gt^2\\\\h=0-\frac{1}{2}gt^2~=>t=\sqrt{2gh}=\sqrt{2*10\frac{m}{s^2}*6m}=10.9544~seg[/tex]

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