Answer:
first term = 15
second term = 9
Third term = 3
Step-by-step explanation:
Let the first term be 3x
Let the second term be = 3x - 6 [ 6 less than first term]
Let the third term be = 1/5 of 3x
[tex]=\frac{1}{5} \times 3x\\\\=\frac{3}{5}x[/tex]
Difference between first and third term = 12
That is ,
[tex]3x - \frac{3}{5}x = 12\\\\\frac{(3x \times 5) - 3x }{5} = 12\\\\15x - 3x = 12 \times 5\\\\12x = 60\\\\x = \frac{60}{12} = 5\\\\Therefore , \ first \ term = 3x = 3 \times 5 = 15\\\\second \term = 3x - 6 = 3( 5) - 6 = 15 - 6 = 9\\\\Third \ term = \frac{1}{5} \times 3x = \frac{1}{5} \times (3 \times 5) = 3[/tex]
