Answer:
Step-by-step explanation:
The change of base formula is
[tex]log_a(b)=\frac{log_{10}b}{log_{10}a}[/tex] so filling in our given:
[tex]log_{13}}(297)=\frac{log_{10}297}{log_{10}13}[/tex] (Note: you do not have to put the base of 10 in the change of base formula because the "normal" base for a log is 10 and that is how your calculator figures it.)
Do this on your calculator to get
[tex]\frac{log297}{log13}=2.2198[/tex] Not sure how many decimal places you needed!
