Answer:
[tex]\displaystyle y=\frac{1}{2}x+5[/tex]
Step-by-step explanation:
We want to find the slope in slope-intercept form of a line that is parallel to:
[tex]\displaystyle y=\frac{1}{2}x-2[/tex]
And passes through the point (-8, 1).
Recall that parallel lines have equivalent slopes.
Since the slope of our given line is 1/2, the slope of our new line must also be 1/2.
We are also given that it passes through the point (-8, 1). Since we are given a slope and a point, we can use the point-slope form:
[tex]y-y_1=m(x-x_1)[/tex]
Substitute 1/2 for m and (-8, 1) for (x₁, y₁). Hence:
[tex]\displaystyle y-(1)=\frac{1}{2}(x-(-8))[/tex]
Since we want the equation in slope-intercept form, we can isolate y. Distribute:
[tex]\displaystyle y-1=\frac{1}{2}x+4[/tex]
Therefore, our equation is:
[tex]\displaystyle y=\frac{1}{2}x+5[/tex]
