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A boy is moving a stone in a horizontal circle by mean of a thread attached to ut. The length if the threads us 1 m and the weight of the stone is 0.02 kg . The maximum tension of the thread can withstand us 1 ×10 ^-4 N. The boy is gradually increasing the speed if rotation. At what speed if the stone does the thread break ? ​

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Luv2Teach

Answer:

Explanation:

This is a centripetal force problem where tension supplies the centripetal force needed to keep the stone moving in a circular manner. That formula for that is

[tex]F_c=T=\frac{mv^2}{r}[/tex] and filling in what we know:

[tex]1*10^{-4}=\frac{.02v^2}{1}[/tex] and solve that for v:

[tex]v=\sqrt{\frac{1*10^{-4}}{.02} }[/tex] which gives us a velocity of .07 m/s. Anything greater than this will break the string.

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