Answer:
21.36 meters
Step-by-step explanation:
Given
[tex]h = 37m[/tex]
[tex]\theta = 60^o[/tex]
Required
The distance from the base (b)
The question illustrates right-angled triangle (see attachment)
To solve for (b), we make use of tangent formula
[tex]\tan(60)=\frac{h}{b}[/tex]
Make b the subject
[tex]b =\frac{h}{\tan(60)}[/tex]
So:
[tex]b =\frac{37}{\tan(60)}[/tex]
[tex]b =\frac{37}{1.7321}[/tex]
[tex]b =21.36[/tex]
