Answer:
B
Step-by-step explanation:
Let divide g(x) by f(x)
[tex] \frac{ {x}^{2} - 9 }{2 - x {}^{ \frac{1}{2} } } [/tex]
The domain of a rational function cannot equal zero so let set the bottom function to zero.
[tex]2 - x {}^{ \frac{1}{2} } = 0[/tex]
[tex]x {}^{ \frac{1}{2} } = 2[/tex]
Square both sides
[tex]x = 4[/tex]
Also we can simplify the bottom denomiator into a square root function
[tex]2 - \sqrt{x} [/tex]
The domain of a square root function is all real number greater than or equal to zero because a square root of a negative number isn't graphable.
So we must find a answer that
- Disincludes 4 from the interval
- Doesnt range in the negative number or infinity)
- Range out in positve infinity
- The answer to that is B
