If PN=14, NO=20, PO=16, QR=55, and SR=44, find the perimeter of ΔQRS. Round your answer to the nearest tenth if necessary

If PN14 NO20 PO16 QR55 and SR44 find the perimeter of ΔQRS Round your answer to the nearest tenth if necessary class=

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Answer:

The perimeter of QRS is 137.5

Step-by-step explanation:

From the given interval angles, we can see that the two triangles are congruent

so it is expected that the ratios of their corresponding sides are equal

this is because; 83 + 53 + 44 = 180

Now, let us work with the side facing the angle marked 53 in both triangles

For the smaller, we have the measure as 16

for the bigger, we have the measure as 44

So the scale factor here is 44/16 = 11/4 = 2.75

We have to multiply the measure of the sides of the smaller triangle by 2.75 to get that of the bigger triangle

in similar vein, we have to multiply the perimeter we have in the smaller triangle by 2.75 to get that of the bigger triangle

The perimeter of the smaller would be the sum of the side lengths

we have this as;

14 + 20 + 16 = 50

So the perimeter of the bigger triangle would be;

2.75 * 50 = 137.5