Let the sides of the triangle ABC be 3x , 4x and 5x.
Perimeter of triangle = 3x + 4x + 5x
[tex] \bf \rightarrow \: 96 \: = \: 12x[/tex]
[tex]\bf \rightarrow \: \frac{96}{12} \: = \: x \\ [/tex]
[tex]\bf \rightarrow \: \cancel\frac{96}{12} \: ^{8} \: = \: x \\ [/tex]
[tex]\bf \rightarrow \: x \: = \: 8[/tex]
Required sides are :
[tex] \bf \implies \: 3x \: = \: 3 \: \times \: 8 \: = 24[/tex]
[tex]\bf \implies \: 4x \: = \: 4 \: \times \: 8 \: = 32[/tex]
[tex]\bf \implies \: 5x \: = \: 5 \: \times \: 8 \: = 40[/tex]
Hence , the sides of the triangle are 24 , 32 and 40.
