Answer:
sinF = [tex]\frac{11}{61}[/tex]
Step-by-step explanation:
sinF = [tex]\frac{opposite}{hypotenuse}[/tex] = [tex]\frac{EG}{FE}[/tex] = [tex]\frac{11}{61}[/tex]
The ratio which represents the sine of ∠F is [tex]\frac{11}{61}[/tex].
In a right angled triangle, the sine of an angle is the length of the side opposite the angle divided by the length of the hypotenuse.
sin θ = opposite side w.r.t θ / hypotenuse
According to the given question
We have
A right angle triangle EFG, in which
∠G = 90 degree
EG = 11
FE = 61
and, GF = 60
Now, the opposite side with respect to ∠F is GE
and the hypotenuse is EF
Therefore, sine of ∠F = side which is opposite w.r.t ∠F/ hypotenuse
⇒ [tex]sinF=\frac{GE}{EF}[/tex]
⇒ [tex]SinF=\frac{11}{61}[/tex]
Hence, the ratio which represents the sine of ∠F is [tex]\frac{11}{61}[/tex].
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