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What are the solutions to the quadratic equation 3(x - 4)2 = 75?
O x = -9 and x = 1
O x = -5 and x = 5
O x = -4 and x = 4
O x = -1 and x = 9

What are the solutions to the quadratic equation 3x 42 75 O x 9 and x 1 O x 5 and x 5 O x 4 and x 4 O x 1 and x 9 class=

Respuesta :

Answer:

4th option, x = -1 and x = 9

Step-by-step explanation:

3(x-4)²=75

or, (x-4)²=25

or, x²-8x+16-25=0

or, x²-8x-9=0

or, x²-9x+x-9=0

or, x(x-9)+1(x-9)=0

or, (x-9)(x+1)=0

so, x-9=0 or, x=9

and x+1=0 or, x=-1

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The two solutions of the quadratic equation are:

x = -1 and x = 9

How to solve the quadratic equation?

The quadratic equation is:

3*(x - 4)^2 = 75

We can expand it as:

3*x^2 - 3*2*4*x + 3*16 = 75

3x^2 - 24x  -27 = 0

Now, using Bhaskara's formula we get:

[tex]x = \frac{-(-24) \pm \sqrt{(-24)^2 - 4*3*(-27)} }{2*3} \\\\x = \frac{24 \pm 30 }{6}[/tex]

So the two solutions are:

x = (24 + 30)/6 = 9

x = (24 - 30)/6 = -1

If you want to learn more about quadratic equations:

https://brainly.com/question/1214333

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