To determine which of the rectangles has a different area, the areas of the four rectangles must be calculated. The rectangle with a different area is rectangle b
The dimension of the 4 rectangles are:
a. length: 4x and width: 4
b. length: 11 and width: x
c. length: 2 and width: 8x
d. length: 16x and width: 1
The area of a rectangle is:
[tex]Area = Length \times Width[/tex]
Rectangle (a)
[tex]Area = 4x \times 4[/tex]
[tex]Area = 16x[/tex]
Rectangle (b)
[tex]Area = 11 \times x[/tex]
[tex]Area = 11x[/tex]
Rectangle (c)
[tex]Area = 2 \times 8x[/tex]
[tex]Area = 16x[/tex]
Rectangle (d)
[tex]Area = 16x \times 1[/tex]
[tex]Area = 16x[/tex]
Rectangles (a), (c) and (d) have the same area (i.e. 16x) while rectangle (b) has 11x as its area.
Hence, the rectangle with a different area is rectangle (b).
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