This question is solved using a system of equations, and doing this, we get that: There are 9 quarters, 4 nickels and 12 dimes.
I am going to say that:
x is the number of nickels.
y is the number of dimes.
z is the number of quarters.
In all, they are worth $3.65.
A nickel is worth $0.05, a dime is worth $0.1 and a quarter is worth $0.25, so:
[tex]0.05x + 0.1y + 0.25z = 3.65[/tex]
Dimes: 3 times greater than nickels:
This means that:
[tex]y = 3x[/tex]
Quarters: One greater than double the number of nickels:
This means that:
[tex]z = 2x + 1[/tex]
Value of x:
We have y and z as function of x, so we can replace into the equation and find the value of x, so:
[tex]0.05x + 0.1y + 0.25z = 3.65[/tex]
[tex]0.05x + 0.1(3x) + 0.25(2x+1) = 3.65[/tex]
[tex]0.05x + 0.3x + 0.5x + 0.25 = 3.65[/tex]
[tex]0.85x = 3.4[/tex]
[tex]x = \frac{3.4}{0.85}[/tex]
[tex]x = 4[/tex]
y and z:
[tex]y = 3x = 3(4) = 12[/tex]
[tex]z = 2x + 1 = 2(4) + 1 = 9[/tex]
There are 9 quarters, 4 nickels and 12 dimes.
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