Respuesta :

ferrybukantoro

Step-by-step explanation:

X^(a²-b²+c²-a²+b²-c²) / X^(c(a-b)+b(c-a)+a(b-c))

= X^(0) / X^(ac-bc+bc-ab+ab-ac)

= X^0 / X^0

=1 / 1

= 1

mhanifa

Answer:

  • 1

Step-by-step explanation:

  • [tex](\frac{x^{a+b}}{x^c})^{a-b}*(\frac{x^{c+a}}{x^b})^{c-a}*(\frac{x^{b+c}}{x^a})^{b-c} =[/tex]
  • [tex]\frac{x^{a^2-b^2}}{x^{c(a-b)}}*\frac{x^{c^2-a^2}}{x^{b(c-a)}}*\frac{x^{b^2-c^2}}{x^{a(b-c)}} =[/tex]
  • [tex]\frac{x^{a^2-b^2+c^2-a^2+b^2-c^2}}{x^{c(a-b)+b(c-a)+a(b-c)}} =[/tex]
  • [tex]\frac{x^0}{x^0} =[/tex]
  • 1

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