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Answer:
2a. (360x +495)/(8x +11) = 45
2b. 2((8x+11) +45) = 16x +112
Step-by-step explanation:
a) The area is the product of length and width.
A = LW
We are given ...
W = 8x +11
A = 360x +495
The value of length can be found by solving for L:
L = A/W
L = (360x +495)/(8x +11)
The long-division solution to this is shown in the attachment.
L = 45 . . . . simplified expression for length
__
b) The perimeter of the tank is twice the sum of length and width:
P = 2(L +W)
Substituting the values for L and W, this is ..
P = 2(45 +(8x +11)) . . . . expression for length of edge seal
P = 2(8x +56)
P = 16x + 112 . . . . . . simplified expression for seal length
