Answer:
Explanation:
The 2 equations we need here are, first:
[tex]a=\frac{v_f-v_0}{t}[/tex] and then once we solve for the acceleration here:
[tex]v^2=v_0^2+2a[/tex]Δx
Solving for acceleration:
[tex]a=\frac{6-4}{10}=\frac{1}{5}\frac{m}{s^2}[/tex] and now we will use that in the other equation:
[tex]6^2=4^2+2(\frac{1}{5})[/tex]Δx and
36 = 16 + [tex]\frac{2}{5}[/tex]Δx and
20 = [tex]\frac{2}{5}[/tex]Δx and
[tex]\frac{5}{2}(20)=[/tex] Δx so
Δx = 50 m
