Answer:
The height of tallest building in Franklin is [tex]\[\frac{431}{8}\][/tex] feet or [tex]53\[\frac{7}{8}\][/tex] feet.
Step-by-step explanation:
Given:
The height of tallest building in Mayville is [tex]80\[\frac{13}{16}\][/tex] feet or [tex]\[\frac{1293}{16}\][/tex] feet. (Simplifying the fraction)
And the tallest building in Franklin is 2/3rd of the tallest building in Mayville.
So, multiply the height of Mayville with [tex]\[\frac{2}{3}\][/tex] to get the height of tallest building in Franklin.
Thus, the height of tallest building in Franklin will be,
[tex]h=\[\frac{1293}{16}\]\times\frac{2}{3}\\h=\frac{431}{8}\\h=53\frac{7}{8}[/tex]
The height of tallest building in Franklin is [tex]\[\frac{431}{8}\][/tex] feet or [tex]53\[\frac{7}{8}\][/tex] feet.
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https://brainly.com/question/6201432?referrer=searchResults
