The force required to keep the worker rom falling off the platform is 120.07 N.
Given data:
The mass of merry go round is, m = 45 kg.
The distance from the center of merry go round is, s = 6.3 m.
The speed of worker is, v = 4.1 m/s.
In this problem, the worker is having a circular motion in merry go round. So the force necessary to keep the worker on track is Centripetal force. And the expression for the centripetal force is,
[tex]F = \dfrac{mv^{2}}{L}[/tex]
Solving as,
[tex]F=\dfrac{45 \times 4.1^{2}}{6.3}\\\\F = 120.07 \;\rm N[/tex]
Thus, we can conclude that the force required to keep the worker rom falling off the platform is 120.07 N.
Learn more about the centripetal force here:
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