contestada

A typical gold bar has dimensions of 82 mm long, 45 mm wide and 16 mm deep. The current price for
gold is $1,368 per ounce (mass).

a. What is the total surface area, in square inches, of the gold bar?
b. Determine how many mL of gold were used to make the gold bar?
c. If the density of gold is 19.3 g/cm^3, what would be the cost of this gold bar?

Please show all the work.

Respuesta :

(a) The total surface area of the gold bar is 17.73 in²

(b) The volume of the gold bar is 59.04 mL

(c) The cost of the gold bar is $54,979.92

The given parameters;

length, L = 82 mm = 3.23 cm

width, W = 45 mm = 1,77 cm

depth, d = 16 mm = 0.63 cm

current price, = $1,368 per ounce

(a) The total surface area of the gold bar;

[tex]T.S.A = (2lw + 2lh + 2wh)\\\\T.S.A = 2(3.23\times 1.77) + 2(3.23 \times 0.63) + 2(1.77 \times 0.63)\\\\T.S.A = 17.73\ in^2[/tex]

(b) The volume of the gold bar

[tex]volume = lwh\\\\volume = 82 \ mm \times 45 \ mm \times 16 \ mm\\\\volume = 59,040 \ mm^3[/tex]

volume in mL = 59.04 mL

(c) The cost of the gold bar is calculated as follows;

The mass of the gold bar is calculated as;

[tex]\pi mass = density \times volume\\\\mass = 19.3 g/cm^3 \times 59.04 \ cm^3\\\\note: 1 \ mL = 1 \ cm^3\\\\mass = 1139.47 \ g\ \ = \ 40.19 \ ounce[/tex]

The cost of the gold:

[tex]cost = \frac{\$ 1,368}{ounce} \times 40.19 \ ounce = \$ 54,979.92[/tex]

Learn more here: https://brainly.com/question/952755