Respuesta :

Answer:

• Considering the (x - 6):

[tex]{ \tt{(x - 6) = 0}} \\ \\ { \boxed{ \tt{ \: \: x _{1} = 6 \: \: }}}[/tex]

• considering the (7x - 3):

[tex]{ \tt{7x - 3 = 0}} \\ { \tt{7x = 3}} \\ \\ { \boxed{ \tt{ \: \: x _{2} = \frac{3}{7} \: \: }}}[/tex]