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XY is the diameter of a semicircle. XY is of length 10.2cm.
The point Z lies on the curved side of the semicircle such that XZ is 5.9cm.
What is the distance from Z to Y?

Respuesta :

ferrybukantoro

Step-by-step explanation:

the distance from Z to Y =

√10.2² - 5.9²

=√104.04 - 34.81

=√ 69.23

= 8.3 cm

[tex]\\ \sf\longmapsto ZY^2=XY^2-XZ^2[/tex]

[tex]\\ \sf\longmapsto ZY^2=10.2^2-5.9^2[/tex]

[tex]\\ \sf\longmapsto ZY^2=104.04-34.81[/tex]

[tex]\\ \sf\longmapsto ZY^2=69.23[/tex]

[tex]\\ \sf\longmapsto ZY=\sqrt{69.23}[/tex]

[tex]\\ \sf\longmapsto ZY=8.3cm[/tex]

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