The characteristics of the black body radiation allow to find that the correct answer for wave enision of a volcano is:
B. The orange of the rock shows that the volcano has some energy emitted in the visible spectrum
Black body radiation is the electromagnetic energy emitted by an ideal body called a black body where all radiation is emitted and absorbed, one of the most important characteristics is that the emission depends on the temperature of the body, but not on the materials that make it up. form. Real bodies approximate a black body using a scalar factor called emissivity.
The graph shows the emission of the black body for various temperatures, we can see that the intensity of the emission decreases significantly with the temperature, also there is a shift towards the infrared as the temperature decreases.
The average temperature of volcanic lava is between 850º and 1200ºC, let's reduce it to degrees Kelvin to facilitate comparison
T₁ = 850 + 273 = 1123K
T₂ = 1200 + 273 = 1473K
When observing the graph we can see that the emission moves towards the infrared when the temperature decreases and the intensity of the emission also decreases with the temperature, in all cases there is a maximum given by the Wien displacement law
λ T = 2,898 10⁻³
λ = [tex]\frac{2.898 \ 10_{-3}}{T}[/tex]
λ = [tex]\frac{2.898 \ 10_{-3} }{1500}[/tex]
λ = 1.93 10⁻⁶m
λ = 1.93 10³ nm
This radiation peak is in the near infrared and is perceived in the form of heat.
Let's analyze the different claims
A. False. To have ultraviolet emissions you need higher temperatures of around 6000K or more.
B. true. The tail of the has emission dye a small part in the visible
C. False. It is the other way around, infrared emission has a longer wavelength than ultraviolet
D. False. The emission approaches a black body therefore the emitter is a continuum with many wavelengths.
In conclusion, using the characteristics of the black body radiation we can find that the correct answer is:
B. The orange of the rock shows that the volcano has some energy emitted in the visible spectrum
Learn more here: brainly.com/question/17446721
