Solution :-
Method-1:-
From the given figure:
∠BOD = 2y°
∠DOC = 3y°
∠COA = 5y°
We know that
The sum of the angles lie on the same line = 180°
=> ∠BOD + ∠DOC + ∠COA = 180°
=> 2y° + 3y° + 5y° = 180°
=> 10y° = 180°
=> y° = 180°/10
=> y° = 18°
Therefore, y = 18°
Method-2:-
From the given figure:
∠BOD = 2y°
∠DOC = 3y°
∠COA = 5y°
We know that
∠COA = 90°
=> 5y = 90°
=> y = 90°/5
=> y = 18°
Method-3:-
From the given figure:
∠BOD = 2y°
∠DOC = 3y°
∠COA = 5y°
We know that
∠BOC+∠DOC = 90°
Since they are complementary angles
=> 2y+3y = 90°
=> 5y = 90°
=> y = 90°/5
=> y = 18°
Therefore, y = 18°
Answer:-
The value of y for the given problem is 18°
Used formulae:-
→ The sum of the angles lie on the same line = 180°
→ The sum of two angles is 90° then they are called Complementary angles.
