Answer:
14 m/s^2
Explanation:
[tex]v_{f}=V_{i} +at[/tex]
[tex]V_{f}=[/tex]final velocity
[tex]V_{i}=[/tex]initial velocity
a= acceleration
t=time
Initial velocity is zero, since the rock was originally at rest and time is 6 seconds.
You are looking for the final velocity, but you need acceleration to find it. Remember that:
[tex]F=m*a[/tex]
Where F is force, m is mass, and a is acceleration. You know force is 7.0 N and mass is 3.0 kg. Use these to find a.
[tex]7.0 N= 3*a[/tex]
[tex]\frac{7}{3} = a[/tex]
So now...
[tex]v_{f}=V_{i} +at[/tex]
[tex]v_{f}=0 +(\frac{7}{3}) (6)[/tex]
[tex]v_{f}= 14 m/s^{2}[/tex]
