The horizontal acceleration of a 1.1 kg toy pulled by a first toddler with a force of 2.5 N and by a second toddler with a force of 3.1 N in the opposite direction is 0.55 m/s².
To find the horizontal acceleration of the toy, we need to calculate the resultant force.
[tex] F_{net} = F_{1} + F_{2} [/tex]
Where:
F₁: is the pulling force of the first toddler = 2.5 N
F₂: is the pulling force of the second toddler = 3.1 N
Taking the direction of the second force as the positive direction, we have:
[tex] F_{net} = -F_{1} + F_{2} = (-2.5 + 3.1) N = 0.6 N [/tex]
Now, we can find the acceleration
[tex] F_{net} = ma[/tex]
Where:
m: is the mass = 1.1 kg
The acceleration is:
[tex] a = \frac{F_{net}}{m} = \frac{0.6 N}{1.1 kg} = 0.55 m/s^{2} [/tex]
Therefore, the horizontal acceleration of the toy is 0.55 m/s².
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