Answer:
Explanation:
conservation of momentum
initial momentum is zero
Lets say that m₁ moves along the x axis
and m₂ moves along the y axis
in the y direction
0 = m₁(0) + m₂(30) + m₃(vy)
0 = m₁(0) + m₂(30) + 3m₂(vy)
-3m₂(vy) = m₂(30)
vy = -10 m/s
in the x direction
0 = m₁(30) + m₂(0) + m₃(vx)
0 = 2m₂(30) + m₂(0) + 3m₂(vx)
-3m₂(vx) = 2m₂(30)
vx = -20 m/s
v = √(-10² + -20²) = 10√5 m/s ≈ 22.36 m/s
θ = arctan(-10/-20) = 206.56505... ≈ 206.6° CCW from the + x axis
