Answer:
For b. 11*3x = 33x
For c. (3x-4)(11x-2) = [tex]33x^{2} -50x+8[/tex]
Explanation:
For b. Since it is a rectangular the A = l*w
w = 11 & l = 3x => A = 11*3x = 33x
For c. Since it is a square we could assume that the A =[tex]s^{2}[/tex] a side squared (since they all have the same length) but to be on the safe side, we'll assume it is not a square and do the math of multiplying one side by another (just like for a rectangle)
Side up = 3x + (-4) = 3x-4
Side left = 11x + (-2) = 11x-2
Side up * Side left = (3x-4)(11x-2) = [tex]33x^{2} -50x+8[/tex]
