Answer:
[tex]19.3 g/cm^3[/tex]
Explanation:
The density of a material is given by
[tex]\rho = \frac{m}{V}[/tex]
where
m is the mass of the sample
V is its volume
for the sample of gold in this problem,
m = 38.6 g
[tex]V=2 cm^3[/tex]
Substituting into the formula, we find the density of gold:
[tex]\rho = \frac{38.6}{2}=19.3 g/cm^3[/tex]
The density of the sample of gold whose mass is 38.6 grams and with a volume of 2 cm³ is 19300 kg/m
Density: This can be defined as the ratio of mass and velocity. The S.I unit of density is kg/m³.
The question above can be solved using the formula below
D = m/V.................... Equation 1
Where D = density of the sample of gold, m = mass of gold, V = volume of gold.
From the question,
Given: m = 38.6 g, = 0.0386 kg, V = 2 cm³ = 0.000002 m³
Substitute these values into equation 1
D = 0.0386/0.000002
D = 19300 kg/m³
Hence the density of the sample of gold is 19300 kg/m³
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