Answer:
There are 6 one dollar bills and 7 five dollar bills.
Step-by-step explanation:
Let the number of $1 bills be x and the number of $5 bills be y
.
x
+
y
=
13
x
+
5
y
=
41
Solve using substitution:
y
=
13
-x
x
+
5
(
13
−
x
)
=
41
x
+
65
−
5
x
=
41
−
4
x
=41
−
65
−
4
x
=−
24
x
=
6
x
+
y
=
13
6
+
y
=
13
y
=
7
Hence, there are 6 one dollar bills and 7 five dollar bills.
