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HI GUYS CAN YOU PLEASE HELP ME!
I NEED THIS ASAP, THNX GUYS
THERES TWO QUESTIONS BTW, THANKS

HI GUYS CAN YOU PLEASE HELP ME I NEED THIS ASAP THNX GUYS THERES TWO QUESTIONS BTW THANKS class=
HI GUYS CAN YOU PLEASE HELP ME I NEED THIS ASAP THNX GUYS THERES TWO QUESTIONS BTW THANKS class=

Respuesta :

Answer:

2a. [tex]54cm^2[/tex]

2b. 78[tex]cm^2[/tex]

Step-by-step explanation:

For 2a, all the squares are similar and this shape forms a cube. Count the boxes for the length and width for 1 square to find the dimensions 3 for the width and 3 for the length. Find the area of that square by doing length*width which in this case is 3 x 3 = 9. Then multiply 9 x 6 because there are 6 squares and get an answer of 54[tex]cm^2[/tex].

For 2b, we know the dimensions for the rectangle 5cm will be the longer side and 3cm will be the shorter side. Find the area of one rectangle using length*width. For one rectangle we get 5 x 3 = 15. Next, we know the square will have sides of 3cm. Do length*width to get the area of one square which is equal to 9. Now that we have the areas for the squares and rectangles, multiply 15 (the area of one rectangle) by 4 because there are 4 similar rectangles. After doing this we get 60. Next do the same thing with squares but multiply by 2 because there are 2 squares. After doing this we get 60 + 18 for the surface area of the figure. 60 + 18 = 78.

Answer:

formula=sa=s*s

3*3=9 FOR ONE SQUARE

they are six squares

9*6=54cm2

the first answer

the second answer

formula=sa=LxW

5*3=15cm

15cm for one rectangle

they are six rectangle

15*6=90cm

Step-by-step explanation:

HOPE THIS IS CORRECT