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A 20 gram bullet strikes a block of wood that has a mass of 2 kg causing the two to move together at 2.5 m/s. How fast was the bullet originally moving out of the gun?

Respuesta :

Answer:

V1i=252.5m/s

Explanation:

Inelastic collision

so the equation should be: m1v1i+m2v2i=(m1+m2)Vf

plug the numbers into the equation: 0.02(v1i)+2(0)=(0.02+2)2.5

so the answer should be: V1i=252.5m/s

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